suatu fungsi di rumuskan oleh f(x) = ax+b.jika f(-2)=14 dab f(3)=-1,maka nilai f(2) adalah
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f(-2) = 14
a ( - 2 ) + b = 14
- 2a + b = 14
f(3) = - 1
a ( 3 ) + b = - 1
3a + b = - 1
- 2a + b = 14
3a + b = - 1
__________ -
- 6a = 15
a = - 15/6
a = - 5/2
- 2a + b = 14
- 2a + ( - 5/2 ) = 14
- 4a - 5 = 28
- 4a = 33
a = - 33 / 4
a = - 8 ¼
f(2)
= - 33/4 (2) - 5/2
= - 33/2 - 5/2
= - 38/2
= - 19
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